Acharge q = 2.00 μc is placed at the origin in a region where there is already a uniform electric field e⃗ = (100 n/c) iˆ . calculate the flux of the net electric field through a gaussian sphere of radius r = 10.0 cm centered at the origin. (ε 0 = 8.85 × 10-12 c2/n · m2)

The flux of the net electric field is

Explanation:

Given that,

Charge

Electric field E = 100 N/C i

Radius R = 10.0 cm

We need to find the flux. It can be calculate using Gauss's law

The flux of the net electric field

Hence, The flux of the net electric field is

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂