Aprojectile is shot from the edge of a vertical cliff 60.0 m above the ocean. it has a speed of 100 m/s and is fired at an angle of 35.0° below the horizontal. how far from the foot of the vertical cliff does the projectile hit the water?

79.5 m

Explanation:

Let t be the time taken to hit the surface of water and x be the horizontal distance traveled.

use II equation of motion in Y axis direction

h = uy t + 1/2 g t^2

- 60 = - 100 Sin 35 x t - 1/2 x 9.8 x t^2

-60 = - 57.35 t - 4.9 t^2

4.9 t^2 + 57.35 t - 60 = 0

By solving we get

t = 0.97 second

The horizontal distance traveled is

x = ux t

x = 100 Cos 35 x 0.97

x = 79.5 m

car a and b are moving in opposite directions

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the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.