Aball rises vertically to a height h and returns to its original point of projection. what is the work done by the gravitational force?

0

Explanation:

When the ball is going upward

The force mg is acting downward and the dispalcement is upward

So, the work done by the gravitational force is - mgh.

When the ball is going downward

The force mg is acting downward and the dispalcement is downward

So, the work done by the gravitational force is  mgh.

The total work done in entire trip is mgh - mgh = 0.

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

answer; /// the above statement is (true);