Calculate the capacitance of a system that stores 2.0 x 10^-10c of charge at 100.0 v. use c=q/v. a. 2.0 x 10^-12 f b. 2.0 x 10^-8 f c. 5.0 x 10^11 f d. 5.0 x 10^7 f

2 x 10⁻¹²F

Explanation:

Capacitance is defined as the ration of charge (q) on either plates to the potential difference V between them.

                        C =

Where  q is the charge on the plates

             V is the potential difference

From the given parameters:

Charge on plate, q = 2.0 x 10⁻¹⁰C

Potential difference across the plate = 100V

Unknown parameter:

Capacitance of the system = ? = C

Solution

        Capacitance = 2.0 x 10⁻¹⁰/100 = 2 x 10⁻¹²F

b

explanation:

bc its just b