2. -/1 pointsserpse10 2.7.p.017.mi. an object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 2.97 cm. if its x coordinate 2.85 s later is -5.00 cm, what is its acceleration? cm/s2 need ? read it master it

-7.86cm/s^2 don’t forget negative sign!

v1=14cm/s
dx=2.97-(-5)=7.97cm
t=2.85s

dx= v1*t+1/2at^2

I’m not writing the unit’s into the equation until the end, but you always should include them in all your calculations!! Units are very important and helpful to solve problems! Anyways, here we go;

7.97=(14*2.85)+1/2a(2.85)^2

a=[(7.97)-(14*2.85)]*2/(2.85)^2

a=(-63.86)/(8.1225)

a=-7.86cm/s^2 don’t forget the negative sign!

Any questions please feel free to ask. Thanks.

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