Acentrifuge in a medical laboratory rotates at an angular speed of 3,700 rev/min. when switched off, it rotates through 54.0 revolutions before coming to rest. find the constant angular acceleration (in rad/s2) of the centrifuge. your response is within 10% of the correct value. this may be due to roundoff error, or you could have a mistake in your calculation. carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. rad/s2

-220 rad/s²

Explanation:

ω² = ω₀² + 2α(θ - θ₀)

We're given that ω = 0 rev/min, ω₀ = 3700 rev/min, and θ - θ₀ = 54.0 rev.

Converting to rad/s:

0 rev/min × (2π rad / rev) × (1 min / 60 s) = 0 rad/s

3700 rev/min × (2π rad / rev) × (1 min / 60 s) = 123⅓π rad/s

54.0 rev × (2π rad / rev) = 108π rad

Plugging in:

(0 rad/s)² = (123⅓π rad/s)² + 2α(108π)

α = -221.2 rad/s²

There's 2 significant figures in 3700 rev/min, so we need to round our answer to 2 sig figs.  The angular acceleration is -220 rad/s².

answer: i pick a

explanation:

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.