Astone is dropped from a tower 100 meters above the ground. the stone falls past ground level and into a well. it hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. calculate the depth of the well. given: g = -9.81 meters/second2.

The distance that an object falls from rest in ' T ' seconds is

           Distance  =  (1/2) (gravity) ( T² )

In this question,

           Distance  =  (1/2) (9.81 m/s²) (5.00 s)²

                         =      (4.905 m/s²) (25.0 s²)

                         =      (4.905 x 25)  m

                         =           122.63 meters .

The first 100 meters of fall was from the tower to ground level,   
so the distance into the well must be the remaining  22.63 meters.

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