Acurrent is induced in a circular loop of radius 1.5 cm between two poles of a horseshoe electromagnet (like that shown in the figure in eddy currents and magnetic damping) when the current in the electromagnet is varied. the magnetic field in the area of the loop is perpendicular to the area and has a uniform magnitude. if the rate of change of magnetic field is 10 t/s, find the magnitude of the induced current if resistance of the loop is 25 ω. report your answer as a positive number in units of ma (milliamps).

its c its is a mixture of gases

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

answer: a. same unit

explanation: