Photoelectrons with a maximum speed of 7.0 x 10^5 m/s are ejected from a surface in the presence of light with a frequency of 8.00 x 10^14 hz. calculate the energy required to eject photoelectrons from the surface

The energy required to eject photoelectrons from the surface is

Explanation:

Given:

Speed of the photo electron=

Frequency of the photoelectron=

To Find:

The energy required to eject photoelectrons from the surface.

Solution:

Energy of the photon is given by

E = hf

Where,

E = energy of the photons

h = Planck’s constant and its value is

Substituting the values in the formula we get ,

E = hf

Result:

Thus a energy of is required to eject thephotoelectrons from the surface

i guess that visual aids present persuasive examples to what you are presenting, some factors would be theme (does it fit with the color, information, what you are presenting), size (can you see it, is it a big enough span of data/information), and overall look of the visual aid.

hope this : )