Physics, 29.06.2019 18:00 khamaari

Massive stars terminate in a brilliant explosion called a

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Answer from: Briza19

Supernova

Explanation:

A supernova explosion occurs when a high mass star ends its life cycle.

When a very massive star runs out of hydrogen used in the core for the nuclear fusion, it starts burning heavier and heavier elements (helium, carbon, etc.). However, this process stops when the star has burnt all elements lighter than iron: in fact, nuclear fusion of the iron cannot occur, since the process releases less energy than the amount of energy needed to start it. At this point, therefore, the star can no longer produce energy by nuclear fusion, and there is no longer any outward pressure that can counterbalance the gravitational force of the star, pushing inward: as a result, the star collapses under the action of gravity, and the outer layers "bounce off the core" producing a huge explosion called supernova.

The remnant of the supernova explosion is, depending on the mass of the star, a neutron star or a black hole.

Answer from: Quest

cant without the picture! ?

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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