Proton with an initial speed of 8 m/s is brought to rest by an electric field.
part a- did the proton move into a region of higher potential or lower potential?
part b - what was the potential difference that stopped the proton?
δu =
part c - what was the initial kinetic energy of the proton, in electron volts?
ki =
best answer
Answers: 3
Physics, 22.06.2019 07:30, luckylady
Select all of the following that are equal to an impulse of 20 unitsa) force= 5, time= 5.5b) force= 25, time= 0.8c) force= 0.1, time= 200d) force= 10, time= 2(its b, c, and d)(also in order to find answer they have to add to get the unit)ex= 25x.8=20 or .1x200=20
Answers: 1
Physics, 22.06.2019 16:50, JeroMii
Two loudspeakers, 5.5 m apart and facing each other, play identical sounds of the same frequency. you stand halfway between them, where there is a maximum of sound intensity. moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.33 m . assume the speed of sound is 340 m/s. part a) what is the frequency of the sound? part b) if the frequency is then increased while you remain 0.21 m from the center, what is the first frequency for which that location will be a maximum of sound intensity? express your answer to two significant figures and include the appropriate units.
Answers: 2
Proton with an initial speed of 8 m/s is brought to rest by an electric field.
part a- d...
part a- d...
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