Aconstant voltage is applied across a circuit. if the resistance in the circuit is doubled, what is the effect on the power dissipated by the circuit?

a. the power dissipated is quadrupled

b. the power dissipated is reduced by a factor of 2.

c. the power dissipated is reduced by a factor of 4

d. the power dissipated is doubled.

e. the power dissipated remains constant.

b.The power dissipated is reduced by a factor of 2.

Explanation:

The power dissipated in the circuit is given by

where

V is the voltage

R is the resistance

In this problem:

- The voltage V is kept constant

- The resistance is doubled, so R' = 2R

Therefore, the new power dissipated is

so, the power dissipated is reduced by a factor of 2.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.