Astring attached to an oscillator at one end forms 5 nodes (counting the two ends) and produces a frequency of ν = 1.5 khz. the string is l = 1.2 m long and is under a tension of t = 276 n.

what is the linear density of the string, in kilograms per meter?

Explanation:

The order of the harmonics for standing waves in a string is equal to the number of nodes minus 1, so

n = 5 - 1 = 4

In this case, the frequency of the 4th-harmonic is

We also know the relationship between the frequency of the nth-harmonic and the fundamental frequency:

so we find the fundamental frequency:

The fundamental frequency is given by

where

L = 1.2 m is the length of the string

T = 276 N is the tension in the string

is the linear density

Solving the equation for , we find

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

there are no contact forces mentioned on the list of choices that you've provided.