Physics, 24.01.2020 19:31 daryn1234

About how much pressure do the feet of a 6000 kg elephant exert on the ground? assume each foot has an area of 0.10 square meter.

i already know the answer but i was just wondering, is the weight of the elephant (6000kg) the force? or would i need to find the force through an equation

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Answer from: duyphan

Approximately 1.5 × 10⁵ Pa.

Explanation:

In simple words, pressure is the normal force per unit area:

$\displaystyle P = \frac{F(\text{Normal Force})}{A}$ ,

where

$F(\text{Normal Force})$ is the magnitude of the normal force on the surface, and

is the area of the contact surface.

What will be the size of the normal force?

Weight of the elephant, which is the same as the gravitational pull on the elephant, will be:

$W = m \cdot g = 6000\times 9.81 = 58860\;\text{N}$ ,

where

is the mass of the elephant, and $g = 9.81\;\text{N}\cdot\text{kg}^{-1}$ is the gravitational field strength (approximately $9.81\;\text{N}\cdot\text{kg}^{-1}$ on the surface of the earth.)

The elephant stands on solid ground. It's not accelerating upward or downward. Forces on the elephant are balanced. As a result, the size of the normal force on the elephant will be the same as that of the earth's gravitational pull on the elephant (not the case in an accelerating elevator.)

$F(\text{Normal Force}) = W = 58860\;\text{N}$ .

Each elephant got four feet. The area of each foot is $0.10\;\text{m}^{2}$ . The total contact area will be $4 \times 0.10 = 0.40\;\text{m}^{2}$ .

Apply the formula. Make sure both the normal force and the contact area are in SI units:

Normal force in Newtons $\text{N}$ , andContact area in Square meters $\text{m}^{2}$ .

If that's the case, the pressure result will be in the unit newtons per square meters $\text{N}\cdot \text{m}^{-2}$ or equivalently, Pascals $\text{Pa}$ .

$\displaystyle P = \frac{F(\text{Normal Force})}{A} = \frac{58860\;\text{N}}{0.40\;\text{m}^{2}} \approx 1.5\times 10^{5}\;\text{N}\cdot\text{m}^{-2} = 1.5\times 10^{5}\;\text{Pa}$ .

Answer from: Quest

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

Answer from: Quest

Is a vector quantity that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

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About how much pressure do the feet of a 6000 kg elephant exert on the ground? assume each foot has...