A525 kg satellite is in a circular orbit at an altitude of 575 km above the earth's surface. because of air friction, the satellite eventually falls to the earth's surface, where it hits the ground with a speed of 1.90 km/s. how much energy was transformed into internal energy by means of air friction? 1445775 incorrect: your answer is incorrect.%20orbit%20at%20an%20alti tude%20of%20575%20km%20above%20the% 20earth's%20surface.%20because%20of %20air%20friction%2c%20the%20satell ite%20eventually%20falls%20to%20the %20earth's%20surface%2c%20where%20i t%20hits%20the%20ground%20with%20a% 20speed%20of%201.90%20km%2fs.%20how %20much%20energy%20was%20transforme d%20into%20internal%20energy%20by%2 0means%20of%20air%20friction%3f%20% 20%20%20j/study? trackid=ae7684c4b7d0& strackid=e93f14d66685& event=enter_submit#p=1

Explanation:

The total energy of the satellite when it is still in orbit is given by the formula

where

G is the gravitational constant

m = 525 kg is the mass of the satellite

is the Earth's mass

r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

So the initial total energy is

When the satellite hits the ground, it is now on Earth's surface, so

so its gravitational potential energy is

And since it hits the ground with speed

it also has kinetic energy:

So the total energy when the satellite hits the ground is

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

pe = weightxheight = 2000x1000=2,000,000joules

close lines strong magnet less close weaker