How much heat is needed to raise the temperature of a 6 g of water by 10°c

10.5 kJ

Explanation:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c

=

4.18

J

g

∘

C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

In water's case, you need to provide  

4.18 J

of heat per gram of water to increase its temperature by  

1

∘

C

.

What if you wanted to increase the temperature of  

1 g

of water by  

2

∘

C

? You'd need to provide it with

Explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft