Aray of light is moving from a material having a high index of refraction into a material with a lower index of refraction.(a) is the ray bent toward the normal or away from it? toward the normalaway from the normal (b) if the wavelength is 600 nm in the material with the high index of refraction, is it greater, smaller, or the same in the material with the lower index of refraction? greatersmaller the same(c) how does the frequency change as the light moves between the two materials? does it increase, decrease, or remain the same? increasedecreaseremain the same

(a) Away from the normal

The direction of bending of the ray of light can be found by using Snell's law:

where

n1, n2 are the index of refraction of the first and second medium, respectively

are the angle of the incident and refracted ray with respect to the normal to the surface, respectively

In this problem, the ray of light moves from a material with high index of refraction to a material with lower index, so:

Re-arranging Snell's law we find

since

we also have

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

where

is the wavelength of the light in a vacuum

n is the refractive index

We can rewrite the equation as

And isolating from the second equation

where

So, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency is the same

While wavelength and speed of a light wave depend on the medium in which the wave is travelling through, the frequency does not depend on that, so it is exactly the same in the two mediums.

we need answer choices

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.