subject
Physics, 01.10.2019 16:00 msmaporter

Perhaps the most-common gravitational calculation is to determine the "weight" of an object of mass mo sitting on the surface of the earth (i. e., the size of the gravitational attraction between the earth and the object). according to newton's law of universal gravitation, the gravitational force on the object is fg=g(memor2e)=(gmer2e)mo, where me is the mass of the earth and re is the distance between the object and the center of the earth (i. e., re = radius of the earth = 6.38×103km). part f what is the value of the composite constant (gme/r^2e), to be multiplied by the mass of the object mo in the equation above? express your answer numerically in meters per second per second.

ansver
Answers: 1

Other questions on the subject: Physics

image
Physics, 22.06.2019 11:00, ronniethefun
If a simple machine reduces the strength of a force, what must be increased?
Answers: 3
image
Physics, 22.06.2019 15:00, deonnaturner68p7hz7y
What sort of waves exhibit the doppler effect?
Answers: 1
image
Physics, 22.06.2019 15:30, salehabajwa101
What are the similarities & differences between a thermistor and a light dependent resistor in physics?
Answers: 1
image
Physics, 22.06.2019 16:30, safiyyahrahman6907
One number is said to be an "order of magnitude" larger than another number if choose one: a. it is 10 times larger. b. it is 5 times larger. c. it is 3 times larger. d. it is 100 times larger. e. it is 2 times larger.
Answers: 1
You know the right answer?
Perhaps the most-common gravitational calculation is to determine the "weight" of an object of mass...

Questions in other subjects:

Konu
Mathematics, 22.09.2020 03:01
Konu
Mathematics, 22.09.2020 03:01
Konu
Mathematics, 22.09.2020 03:01
Konu
English, 22.09.2020 03:01
Konu
Spanish, 22.09.2020 03:01