Consider motion in one dimension. (the sign of the vector quantities is their direction indicator.) an object moves in the positive x-direction with speed 0.9 m/s for 3.6 s. it stops for 4.7 s and then moves in the negative x direction with speed 1 m/s for 2.9 s. what is the total distance traveled by the object in units of meter? enter a number with two digits behind the decimal point.

6.14 m

Explanation:

The motion of the object is divided into three parts:

- Part 1: the object moves with speed

v = +0.9 m/s (the positive sign means positive x-direction)

for t = 3.6 s

Therefore, the distance covered is

- Part 2: the object stops for 4.7 s, so during this time the distance travelled by the object is zero.

- Part 3: the object moves with speed

v = -1 m/s (negative sign means negative x-direction)

for a time of

t = 2.9 s

We are only concerned in the distance travelled, so we can ignore the negative sign, and the distance covered in this part is

So, the total distance covered is

d. air pressure decreases as altitude increases.