Aman pushes a box of 40kg up incline of 15°, if the man applies a horizontal force of 200n and the box moves up the plane a distance of 20m at a constant velocity and the coefficient of friction is 0.1, find work done against friction

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

neither accurate nor precise.