What is the energy stored, in units of nanojoules, on a 14.8 nf capacitor when the voltage applied across the capacitor is 7.2 v?

383.6 nJ

Explanation:

The energy stored in a capacitor is given by the formula:

where

C is the capacitance

V is the voltage applied

In this problem, we have

C = 14.8 nF is the capacitance of the capacitor

V = 7.2 V is the voltage

Substituting into the equation, we find:

found in the nucleus

has mass of one amu

come closer and become far apart and become steam/gas