Rocío strikes a 0.058-kg golf ball with a force of 272n and gives it a velocity of 62.0m/s. how long was ricío club in contact with the ball?

So lets list out we have here:

velocity = 62 m/s

Force = 272 N

Mass = 0.058kg

In studying momentum you learn that the force multiplied by the change in time is equal to the change in momentum.

FΔt = Δp

FΔt = p(final) - p(initial)

The ball is orginally at rest so its momentum is zero because momentum = mass x velocity and if velocity is 0 then the whole equation goes to zero. So...

FΔt = p(final)

Isolating for Δt gives

Δt = p(final) / F

Δt = mv / F

Δt = (0.058)(62) / (272)

Δt = 0.013 seconds

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s