A10 kg box initially at rest is pulled 18 meters across a horizontal, frictionless surface by a 40 n force. what is the block’s final velocity over the 18 meters?

The final velocity of the bock over the given distance is 12m/s.

The acceleration of the block is calculated as follows;

F = ma

a = F/m

a = 40/10

a = 4 m/s²

The final velocity of the bock is calculated using the following kinematic equation;

Thus, the final velocity of the bock over the given distance is 12m/s.

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As per work energy theorem we know that

Work done = change in kinetic energy

so here we will have

here we know that

work done is product of force and displacement

now from above equation we have

here we know that

so we will have

so its speed will be 12 m/s

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