Suppose an object is thrown with the same initial velocity and direction on earth and on the moon, where the acceleration due to gravity is one-sixth its value on earth. how will vertical velocity, time of fight, maximum height, and horizontal distance change? i would appreciate if they were numerical values like doubles or triples. you

As we know that

Time of flight is given by

Vertical height

Horizontal range

vertical speed

now we can see all factors except vertical speed depends on gravity inversely

So here we can say that

Range on moon will increase by 6 times

Maximum vertical height increased by 6 times

Time of flight increased by 6 times

as all above depends inversely on gravity

vertical speed remains unchanged as it is independent of gravity

Let's call

g = acceleration on earth

g '= acceleration on the moon.

We know that:

1. The formula for vertical velocity on earth is:

On the moon, we have:

The vertical speed on the moon is greater than on earth by a factor of gt (5/6)

2. The formula for the time of flight on earth is:

On the moon it is:

The time of flight on the moon is 6 times greater than on earth.

3. The maximum height on earth is:

On the moon:

So:

The maximum height on the moon is 6 times greater than on earth.

4. On earth, the horizontal distance traveled is equal to:

The horizontal distance traveled on the moon is 6 times greater than that of the earth.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6