A500 kilogram roller coaster starts from rest at the top of an 80 meter hill. what was its speed at the bottom at the hill?

m = mass of the roller coaster = 500 kg

h = height of the hill = 80 m

v = speed of the roller coaster at the bottom of the hill = ?

using conservation of energy

kinetic energy at the bottom of the hill = potential energy at the top of hill

(0.5) m v² = m g h

(0.5) v² = g h

inserting the values

(0.5) v² = (9.8) (80)

v = 39.6 m/s

hence the speed at the bottom comes out to be 39.6 m/s

good looking response

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2