An object is dropped from a height of 25 meters. at what velocity will t hit the ground? a.7.0 b.11 c.22 d.49 e.70

Given data

height (h) = 25 m ,

velocity (v) = ?

we know that,

                     v²-u² = 2as

                      initial velocity (u) = 0,

                                                a = g = 9.8 m/s ,

                  Now the equation becomes,

                                     v² = 2 × g × h

                                         = 2 × 9.8 × 25

                                     v² = 490.5

                                     v = √490.5

                                    v = 22.1 m/s

Therefore answer is C , i.e., 22 m/s (If you like this procedure, give me brainiest)

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

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