Satellite a orbits the earth at a height 2.00 times the earth's radius. satellite b orbits the earth at a height 3.00 times the earth's radiuswhat is the ratio of the period of satellite b to the period of satellite a?

From Kepler's law: The cube of radius of the orbit of satellite is proportional to square of time period of orbit.

where, r is the radius of the orbit of satellite, T is the time period of satellite, G is the gravitational constant, m is the mass of the planet.

R is the radius of Earth.

Hence, the ratio of the period of Satellite B to the period of Satellite A is

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weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards