Pitbulllover101 rutherford's famous gold foil experiments shot heavy particles at a thin sheet of gold foil. what did he observe, and why did these observations eventually result in the addition of a nucleus to the atomic model? some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom. some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom. the heavy particles all passed straight through the foil, because the atoms are mostly empty space. the heavy particles all bounced off the foil, because the subatomic particles have mass and volume.

Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.

Explanation:

As per the observation of experiment he observed that very few heavy particles in this experiment bounced off in opposite direction.

Due to this reverse direction motion we can conclude that there must be a small dense region in which there is same charge concentrated which will repel the heavy particle

This region is concluded in very small space because major proportion move out the foil without any deviation only few of the particles will return back.

So here we can say that correct option must be

Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.

pecialized keyboards

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.