Physics, 28.06.2019 09:30 aliay6857

Atruck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical components of the trucks velocity

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Answer from: AleOfficial101

a. The horizontal component of the truck's velocity is 5.69 m/s.

b. The vertical component of the truck's velocity is 21.25 m/s.

Given the following data:

Angle of inclination = 15°Velocity of truck= 22 m/s

To find both the horizontal and vertical components of the truck's velocity:

a. To find the horizontal component of the truck's velocity:

Mathematically, the horizontal component of velocity is given by the formula:

$V_y = Vsin(\theta)\\\\V_y = 22sin(15)\\\\V_y = 22 \times 0.2588$

Horizontal component, Vy = 5.69 m/s

b. To find the vertical component of the truck's velocity:

Mathematically, the vertical component of velocity is given by the formula:

$V_x = Vcos(\theta)\\\\V_x = 22sin(15)\\\\V_x = 22 \times 0.9659$

Vertical component, Vx = 21.25 m/s

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Atruck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the...