3) a driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. if the coefticient of friction between the tires and the level road is 0 80 how long will the skid marks be? a) 37 m b) 30 m c) 34 m d 46 m

A) 37 m

Explanation:

When the driver slams on the brakes, the force of friction acting on the car provides the deceleration that will cause the car to stop, according to Newton's second law:

where

is the coefficient of friction

m = 1000 kg is the mass of the car

g = 9.8 m/s^2

a is the deceleration

Substituting into the formula, we find the deceleration:

Now we can find the length of the skid with the SUVAT equation:

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

d is the length of the skid

Substituting, we find

the rearrangement of particles in a physical change. hope this

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.