The image of an object formed by a mirror is real inverted and is magnification -1. if the image is at the distance of 30 cm from the mirror where is the object placed find the position of the image if the object is now moved 20cm towards the mirror what is the nature of the image obtained justify your answer with the of a ray diagram

The nature of the image is magnified , virtual , and upright.

We will solve this problem using following formula:

where:

so = distance of object from mirror

si = distance of image from mirror

f = focal length of mirror

Given:

Magnification = M = 1

Initial Image Distance = si = 30 cm

Difference of Object's Distance = Δso = 20 cm

Unknown:

Final Image Distance = si' = ?

Solution:

Because si' < 0 , the nature of the image will be magnified , virtual , and upright.

Grade: High School

Subject: Physics

Chapter: Light

Keywords: Light , Mirror , Magnification , Ray , Diagram , Image , Real , Virtual

overcharge is the right answer system

the answer is 12 as i may remember

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