Amotorbike accelerates from 15m/s to 25m/s in 15 seconds. how far does the motorbike travel in this time?

The distance traveled by the motorbike is 300 m.

How do you calculate the distance?

Given that initial velocity u is 15 m/s and final velocity v is 25 m/s within the time t = 15 seconds.

The distance covered by the motorbike is calculated by the formula given below.

Hence we can conclude that the distance traveled by the motorbike is 300 m.

To know more about the velocity and distance, follow the link given below.

link.

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero.