Abead of mass m = 5.0 kg is released from point a and slides on the frictionless track shown above. note that the bead slides, it doesn't roll, because there's no friction at all. (a) what is the total mechanical energy initially? - answer is 245 j (b) determine the bead's speed at point c? - answer is 7.67 m/s i have no clue how to solve this pls picture is attached!

The correct answer to the question is : (A) 245 J and (B) 7.92 m/s

EXPLANATION :

As per the question, the mass of the bead m = 5.0 Kg.

The height of the point A from the ground h = 5 m.

First we are asked to calculate the energy of the bead at point A.

The energy possessed by the bead at the point A is the gravitational potential energy.

Hence, the gravitational potential energy of the bead at the point A is calculated as -

 Potential energy P.E = mgh

                                    = 5 × 9.8 × 5 joule

                                   = 245 J.                     [ANS]

Now we are asked to calculate the velocity at point C.

The potential energy of the bead at point B is equal to the kinetic energy of the bead at point C . It is so because the potential energy of the bead gradually converts into into kinetic energy when the bead comes from    point B to point C.

Hence, potential energy at B = Kinetic energy at C.

          ⇒  mgh =

          ⇒  2gh =

          ⇒ v =

                 =

                 = 7.92 m/s.                            [ans]

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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