An air pump does 5,600 j of work to launch a water bottle rocket into the air. if the air pump applies 150 n of force to the rocket at an angle of 45° to the ground, what is the horizontal distance the water bottle rocket travels? round your answer to two significant figures.

5.3 × 10^1 m

Explanation:

53 m

Explanation:

Work = Force × Displacement

W= F s cosΘ

Where, s is the displacement and F is the force. Θ is the angle between force and displacement

F cosθ is the component of force acting in the horizontal direction.

The air pump applies F = 150 N force at an angle Θ = 45°

W = 5600 J

⇒s = W/F cosθ

Thus, the horizontal distance the water bottle rocket travels is 53 m

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.