The flowers of the bunchberry plant open with astonishing force and speed, causing the pollen grains to be ejected out of the flower in a mere 0.30 ms at an acceleration of 2.5×104m/s2. part a with what speed are pollen grains ejected from a bunchberry flower? express your answer using two significant figures. is the bee likely to notice?

As we know that pollens are ejected out from rest

So its initial speed is

acceleration of the pollen that comes out is

now it took time

so we will use kinematics to find out the speed with which it will ejected out

so final speed will be 7.5 m/s

Pollen grains speed : 7.5 m/s

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• An equation of uniformly accelerated motion

x = distance on t

vo / vi = initial speed

vt / vf = speed on t / final speed

a = acceleration

Acceleration is a change in speed within a certain time interval

The velocity graph with respect to time (v-t) in this motion will be in the form of sloping straight lines with a gradient of tan θ = a

For acceleration that is positive (a> 0) is called accelerated motion, the graph is sloping upward, while for acceleration that is negative (a <0) is called slowed down motion, the graph is sloping downward

The pollen grains to be ejected out of the flower in 0.30 ms at an acceleration of 2.5×10⁴m/s², then :

Δt = 0.3 ms = 3.10⁻⁴ s  

a = 2.5 × 10⁴ m/s²

so :

The distance of the elevator  

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resultant velocity  

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the average velocity  

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can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

answer///scientific method;