Suppose the odometer on our car is broken and we want to estimate the distance driven over a 30 second time interval. we take the speedometer readings every five seconds and record them in the following table. time (s) 0 5 10 15 20 25 30 velocity (mi/h) 16 21 23 26 33 30 28 in order to have the time and the velocity in consistent units, let's convert the velocity readings to feet per second (1 mi/h = 5280 3600 ft/s). (roun

Let say for every 5 s of time interval the speed will remain constant

so it is given as

v(mi/h)   16    21    23    26    33    30     28

now we have to convert the speed into ft/s as it is given that 1 mi/h = 5280/3600 ft/s

so here we will have

v(ft/s)      23.5    30.8     33.73     38.13     48.4     44     41.1

now for each interval of 5 s we will have to find the distance cover for above interval of time

so here it will cover 1298.1 ft distance in 30 s interval of time

battery with hi vtge high val resist in series

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west