How far apart are a 900kg car and an 80kg man if they experienced a gravitational attraction of 1 n?

The answer would be 2.2 millimeters because although this is basically impossible, you would use the formulas: F = G M₁ M₂ / R²  

G = 6.67 x 10⁻¹¹ m³ / kg - s² to figure out your answer so it would look like this:

(6.67 x 10⁻¹¹) (900) (80) / R²

 (6.67 x 10⁻¹¹ x 900 x 80)

 4.8 x 10⁻⁶

 √(4.8 x 10⁻⁶)

 0.0022 meter

 2.2 millimeters

Hope this helps :)

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2