A50g arrow is fired vertically downward to a target 10m below. if it was released from the bow with a speed of 50m/s, and it lodges itself 15cm into the ground determine the average force that the arrow exerts on the ground ignore air resistance

Speed of the arrow just before it will hit the ground can be calculated by energy conservation

by solving above equation

now this will lodge itself 15 cm into the ground

so after lodging itself to 15 cm the speed of arrow becomes zero

now we will have

Now by Newton's II law net force is given as

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer