A1,800 kg car is parked on a road that has an elevation angle of 7°. suppose the coefficient of static friction of the kinds of rubber and asphalt involved is 0.65. which is approximately the force of static friction between the tires and the road? question options: 11,350 n 9,300 n 18,000 n 2,200 n

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.