You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same speed) brakes and begins to slow down with the largest deceleration possible without skidding. considering an average human reaction, you press your brakes 0.543 s later. you also brake and decelerate as rapidly as possible without skidding. assume that the coefficient of static friction is 0.804 between both cars’ wheels and the road.

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8.1242 m/s^2

Remaining part of the question:

The acceleration of gravity is 9.8 m/s2 . Calculate the acceleration of the car in front of you when it brakes?

Explanation:

Frictional force allow as a  car to stop from motion, but it is also part of the the force required by the the car to move forward, It help keeps the tires from sliding on the road. if you are to correctly calculate the motion of  a body  across a surface, you must take into account  the interactions  between the body and the surface.

ma=μmg

The acceleration of the car can be calculated as

a=μg=(0.829)(9.8)=8.1242 m/s^2

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explanation:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day