Astone is thrown horizontally from 2.4m above the ground at 35m/s. the wall is 14m away and 1m high. at what height the stone will reach? where will the stone land?

The stone reaches the wall at a height of 1.62 m.

The stone lands at a point 24.5 m from the point of projection.

The stone is projected horizontally with a velocity u at a height h from the ground. The wall is located at a distance x from the point of projection. The stone takes a time t to reach the wall and in the same time the stone falls a vertical distance y.

The horizontal distance x is traveled with a constant velocity u.

Calculate the time taken t.

The stone's initial vertical velocity is zero. It falls through a distance y in the time t under the action of acceleration due to gravity g.

The height  h₁ of the stone above the ground when it reaches the wall  is given by,

When the stone reaches the wall, its height from the ground is 1.62m.

The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance R from the point of projection. If the time taken by the stone to reach the ground is t₁, then,

Calculate the time taken by the stone to reach the ground.

The horizontal distance traveled by the stone is given by,

The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.

1/0.14nm = 10^10/1.4 a lot