Acar starts from rest and accelerates at a constant rate of 4.5 m/s^2. what is the final velocity after traveling 1.6 km?

First write down all the known values:

vi = 0m/s

a = 4.5m/s^2

d = 1.6km = 1600m  Remember to convert to meters since the acceleration is in meters

vf = ?

Now use the kinematic equation that relates all these variables:

vf^2 = vi^2 + 2ad

vf^2 = (0)^2 + 2(4.5)(1600)

vf^2 = 14400

vf = 120m/s

The final velocity of the car is 120m/s.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j