Aprojectile is launched horizontally east at a speed of 29.4 m/s towards a wall 88.2 m away. what is the velocity of the projectile at the moment it strikes the wall? a. 29.4 m/s down b. 29.4 m/s east c. 29.4 m/s at 45(degrees) down from horizontal toward the east d. 41.6 m/s at 45(degrees) down from horizontal toward the east

Time before projectile hits wall

= 88.2 m / 29.4 m/s = 3 seconds

Vertical velocity of projectile after three seconds

= 3*9.8 = 29.4 m/s

Horizontal velocity of projectile after three seconds, assuming no air resistance

= 29.4 m/s  (given)

Conclusion:

velocity of projectile when it hits the wall

= < 29.4, -29.4> m/s

= sqrt(29.4^2+29.4^2) m/s east-bound at 45 degrees below horizontal

= 41.58 m/s east-bound at 45 degrees below horizontal.

frequency or wavelenth of em radiation in a vacuum

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y