If you traveled one mile at a speed of 100 miles per hour, and another mile at a speed of 1 mile per hour, your average speed would not be (100 mph+1mph)/2 or 50.5 mph. what would be your average speed? (hint: what is the total distance and total time? ) okay so.. how would i set up this problem and solve properly? maybe it's just me, but the way this is worded is throwing me off. any is greatly appreciated! < 3

The average speed is 1.98 mile per hour.

Explanation:

you traveled one mile at a speed of 100 miles per hour

So, the distance travelled by you is 1 mile

The speed is given by,

Speed = distance/ time

time = distance / speed

time = 1 / 100

time = 0.01 hour

Now next mile you travel at speed 1 mile per hour.

The speed is given by,

Speed = distance/ time

time = distance / speed

time = 1 / 1

time = 1 hour

Total distance = 1 mile + 1 mile = 2 mile

Total time = 1 hour + 0.01 hour = 1.01 hour

Average speed is given by,

Average speed =

Average speed =

Average speed = 1.98 mile per hour

The average speed is 1.98 mile per hour.

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hope this !

a=d/t

a="triangle"v/t

explanation:

a = acceleration