If a seagull drops a shell from rest at a height of 12 m how fast is the shell moving when it hits the rocks

As seagull drops a shell from rest at a height of 12 m, so we use kinematic equation of motion,

Here, h is the height, u is initial velocity , v is final velocity and g is acceleration due to gravity.

Given,  h = 12 m.

We take, and because seagull drops a  shell from rest.

Therefore, the speed of shell when it hits the rocks,

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat