Divers in acapulco, mexico, leap from a point 36m above the sea. what is the velocity when they enter the water? v = distance / time

The velocity is 27.6m/s

Explanation: We know that they leap from a distance of 36m.

We know then that the initial height is equal to 36m, and this means that the initial potential energy is equal to:

U = mgh

where m is the mass, g is the gravity acceleration and h is the height.

Right in the point where the diver touches the water, we have h = 0, and this means that all the potential energy transformed into kinetic energy, that is written as:

K = (1/2)*m*v^2

And from here we can find the velocity in that point.

m*g*h = (1/2)*m*v^2

2*g*h = v^2

v = √(2*g*h)

and g = 9.8m/s^2, h = 39m

v = √(2*9.8m/s^2*39m) = 27.6m/s

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