Arunner at a speed of 3.5 m/s comes to a stop in 0.15 seconds. what is the deceleration?

Deceleration of the runner is -23.33

Given:

Initial velocity = 3.5

Final velocity = 0

Time = 0.15 s

To find:

Deceleration of runner = ?

Formula used:

According to first equation of motion,

v = u + at

Where, v = final velocity

u = initial velocity

a = deceleration

t = time

Solution:

According to first equation of motion,

v = u + at

Where, v = final velocity

u = initial velocity

a = deceleration

t = time

0 = 3.5 + a (0.15)

-3.5 = 0.15 (a)

a =

a = -23.33

Negative sign shows that it is deceleration.

Thus, deceleration of the runner is -23.33

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explanation:

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