Abusy chipmunk runs back and forth along a straight line of acorns that has been set out between its burrow and a nearby tree. at some instant, it moves with a velocity of â’1.47 m/s. then, 2.07 s later, it moves with a velocity of 1.73 m/s. what is the chipmunk's average acceleration during the 2.07 s time interval?

Chipmunk's average acceleration during the 2.07 s time interval = 0.1256

Explanation:

  We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

  In this case we need to find acceleration value, we have initial velocity = 1.47 m/s, final velocity = 1.73 m/s and time taken = 2.07 seconds.

 Substituting

       1.73 = 1.47 + a * 2.07

       a = 0.1256

  Chipmunk's average acceleration during the 2.07 s time interval = 0.1256

33: i think it’s b