Physics, 09.07.2019 23:00 anonymous654
In the late middle ages there was a renewed interest in learning what was the main cause of this?
Answers: 1
Physics, 23.06.2019 08:30, ldmcloon
Apoint charge +q is at the origin. a spherical gaussian surface centered at the origin encloses +q. so does a cubical surface centered at the origin and with edges parallel to the axes. select "true" or "false" for each statement below. the electric flux through the spherical surface is greater than that through the cubical surface. suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. the flux through both surfaces remains unchanged. the area vector and the e-field vector point in the same direction for all points on the spherical surface. the e-field at all points on the spherical surface is equal due to spherical symmetry. the flux through the spherical gaussian surface is independent of its radius.
Answers: 3
Physics, 23.06.2019 10:00, YoVeoAnime
No receiver is named? transitive passive or intrasitive complete
Answers: 2
Physics, 23.06.2019 17:00, isabeltorres5
Conceptualize notice how this problem differs from our previous discussion of gauss's law. the electric field due to point charges was discussed in the previous section. now we are considering the electric field due to a distribution of charge. we found the field for various distributions of charge in the chapter entitled electric fields by integrating over the distribution. this example demonstrates a difference from our discussions in the previous chapter. in this chapter, we find the electric field using law. categorize because the charge is distributed uniformly throughout the sphere, the charge distribution has spherical symmetry and we can apply gauss's law to find the field. analyze note that the following conditions can be used to determine a suitable gaussian surface. condition (1): the value of the electric field can be argued by symmetry to be constant over the portion of the surface. condition (2): the dot product e â· da can be expressed as a simple algebraic product e da because e and da are parallel.
Answers: 3
In the late middle ages there was a renewed interest in learning what was the main cause of this?...
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