Avery small object carrying -6.0 μc of charge is attracted to a large, well-anchored, positively charged object. how much kinetic energy does the negatively charged object gain if the potential difference through which it moves is 3.0 mv

    Kinetic energy gain by a very small object carrying -6.0 μc of charge is attracted to a large, well-anchored, positively charged object = 18 nJ

Explanation:

  The potential energy gained by negatively charge is the change in potential energy between the points.

 So, Kinetic energy = Change in potential energy = qΔV

 In this case q = 6.0 μc = and ΔV = 3.0 mV =

  Substituting

              Kinetic energy gain =

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: